Macro (add a debugger macro)¶

macro macro-name lambda-object

Define macro-name as a debugger macro. Debugger macros get a list of arguments which you supply without parenthesis or commas. See below for an example.

The macro (really a Python lambda) should return either a String or an List of Strings. The string in both cases is a debugger command. Each string gets tokenized by a simple split() . Note that macro processing is done right after splitting on ;;. As a result, if the macro returns a string containing ;; this will not be interpreted as separating debugger commands.

If a list of strings is returned, then the first string is shifted from the list and executed. The remaining strings are pushed onto the command queue. In contrast to the first string, subsequent strings can contain other macros. ;; in those strings will be split into separate commands.

Here is an trivial example. The below creates a macro called l= which is the same thing as list .:

macro l= lambda: 'list .'

A simple text to text substitution of one command was all that was needed here. But usually you will want to run several commands. So those have to be wrapped up into a list.

The below creates a macro called fin+ which issues two commands finish followed by step:

macro fin+ lambda: ['finish','step']

If you wanted to parameterize the argument of the finish command you could do that this way:

macro fin+ lambda levels: ['finish %s' % levels ,'step']

Invoking with:

fin+ 3

would expand to: ['finish 3', 'step']

If you were to add another parameter for step, the note that the invocation might be:

fin+ 3 2

rather than fin+(3,2) or fin+ 3, 2.